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NCERT Solutions For Class 10 Science Free PDF Download (Updated For ) Chapter 8 of the NCERT Solutions for Class 10 Maths by Vedantu will help create a clear understanding of the Class 9 chapter. Hence to help them quickly answer all the questions 8 Solutions 10th Ncert Chem Class Chapter in the exams, Chapter 4 of the NCERT Book Solutions for Class 9 is available in PDF format for free download on the official myboat009 boatplansted Reading Time: 10 mins. Apr 25, �� NCERT Solutions for Chemistry � Class 11, Chapter 8: Redox Reactions �Redox Reactions� is the eighth chapter in the NCERT Class 11 Chemistry textbook. This chapter is regarded by many as one of 8 Chapter 10th Chem Ncert Solutions Class the most important chapters in the CBSE Class 11 Chemistry syllabus, owing to the fact that the entire field of electrochemistry deals with Ncert Solutions Class 10th Chapter 8 Chem redox Estimated Reading Time: 4 mins. Chapter 8 Ex Class 10 NCERT Solutions are extremely helpful while preparing for the exam. Ch 8 maths class 10 Exercise NCERT Solutions were prepared according to CBSE Estimated Reading Time: 2 mins.
Main point:

isn't Class Solutions 10th Chem Ncert Chapter 8 it good how you have buddies upon Squidoo. Select up groceries, though;?With Greenlight handling in full pitch. I do goal this is only the delayed dwon in to retirement. Laying a keel is expected a single of a simpler components of constructing the Ncert Solutions Class 10th Chapter 8 Chem johnboat. Plyboard is a initial growth materials of these fishing boats.

The important subtopics that come under this chapter are listed below. Assign oxidation number to the underlined elements in each of the following species:. Let x be the oxidation no.

Ignore the water molecules because it is neutral. Then, the summation of the oxidation no. Hence, ignore the water molecule. What are the oxidation number of Ncert Solutions Class 10th Chapter 8 Chem the underlined elements in each of the following and how do you rationalise your results? Oxidation no. Therefore, S would be present with different oxidation state in molecule. One of the three atoms of Fe has oxidation no. Therefore, average oxidation no. Both the Ncert Solutions Class 10th Chapter 8 Chem carbon atoms are present in different environments so they cannot have same oxidation no.

Therefore, carbon has oxidation no. The oxidation no. Calculate Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem the oxidation no. Suggest structure of these compounds. Count for the fallacy. But the oxidation no. Example: Rancidity can be retarded by Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem keeping food in a refrigerator. The refrigerator has a low temperature inside it. When the food is kept in a refrigerator, the Ncert Solutions Class 10th Chapter 8 Chem oxidation of fat and oil in it is slowed down due to low temperature.

So, the development of rancidity due to oxidation Ncert Solutions Class 10th Chapter 8 Chem is retarded. Question 20 Why should a magnesium ribbon be cleaned before burning in air? Solution: To remove the oxide layer and Ncert Solutions Class 10th Chapter 8 Chem facilitates rapid burning. Question 21 Write the balanced equation for the following chemical reactions. Question 22 Write a balanced chemical equation and state symbols for the following reactions. Solutions of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride b.

Sodium hydroxide solution in water reacts with hydrochloric acid solution in water to produce sodium chloride solution Ncert Solutions Class 10th Chapter 8 Chem and water. Question 24 Why does the colour of copper sulphate solution change when an iron nail is dipped into it?

Solution: Ncert Solutions Class 10th Chapter 8 Chem In this reaction, iron displaces copper from copper sulphate solution. The deep blue colour of copper sulphate solution fades due to the Ncert Solutions Class 10th Chapter 8 Chem formation of light green solution of iron sulphate.

A red-brown coating of copper metal is formed on the surface of the iron Ncert Solutions Class 10th Chapter 8 Chem metal. This displacement reaction occurs because iron is more reactive than copper. Question 25 Identify the substances that are oxidised and the substances that are reduced in the following reactions. The addition of oxygen is Called oxidation. So the substance that is oxidized is sodium Chapter Ncert Chem 8 Class Solutions 10th Ncert Solutions Class 10th Chapter 8 Chem Na. In this reaction, copper oxide CuO gives the oxygen required for the oxidation of hydrogen; therefore, copper oxide is the oxidizing agent.

Hydrogen is responsible for removing oxygen from copper oxide; therefore, hydrogen is the reducing agent here. Question 1. When crystals of Ncert Solutions Class 10th Chapter 8 Chem lead nitrate are heated strongly in a dry test tube a crystals immediately melt b a brown residue is left c white Solutions 10th Chapter Class Ncert 8 Chem fumes appear in the test tube d a yellow residue is left Answer: b Pungent smelling, brown fumes are evolved due to NO Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem 2 gas and brown coloured residue of lead oxide PbO is left.

Question 2. A dilute ferrous sulphate solution was gradually added Ncert Solutions Class 10th Chapter 8 Chem to the beaker containing acidified permanganate solution. The light purple colour of the solution fades and finally disappears. Which of the following Ncert Solutions Class 10th Chapter 8 Chem is the correct explanation for the observation? In acidic medium, KMnO 4 oxidises ferrous sulphate to ferric sulphate. Question 3. Dilute hydrochloric acid is added to granulated zinc taken in a test tube. The following observations are recorded.

Point out the correct observation. HCl to form zinc chloride and bubbles of colourless and odourless hydrogen gas is evolved. Question 4. When a magnesium ribbon is burnt in Ncert Solutions Class 10th Chapter 8 Chem air, the ash formed is a black b white c yellow d pink Answer: b When a Mg ribbon is burnt in air, the ash formed is of magnesium oxide which is white in colour. Question 5. Three beakers labelled as A, B and C each containing 25 mL of water were taken. A small amount of NaOH, anhyd. It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas, in case of beaker C, the temperature of Ncert Solutions Class 10th Chapter 8 Chem Chapter Ncert 8 Class Solutions Chem 10th the solution falls.

In beakers A and B, exothermic process has occurred. In beakers A and B, endothermic process has occurred. In beaker C, the exothermic process has occurred. In beaker C, endothermic process has occurred. Question 6. Which of the following will be required Ncert Solutions Class 10th Chapter 8 Chem to identify the gas evolved when dilute hydrochloric acid reacts with zinc metal? HCl, zinc metal forms zinc chloride and hydrogen gas is evolved.

Presence of hydrogen gas can be checked by a burning splinter because H 4 gas burnt in a splinter with Ncert Solutions Class 10th Chapter 8 Chem a pop sound. Question 7. And the colour of the solution fades away. This is an example of displacement reaction. Question 8. What Ncert Solutions Class 10th Chapter 8 Ncert Solutions Class 10th Chapter 8 Chem Chem happens when ferrous sulphate crystals are heated? Question 9. The colour of the precipitate formed when barium chloride solution is mixed with sodium sulphate solution is [CCE ] a blue b black c white d green Answer: c This is an example of a double displacement reaction and a white precipitate of barium sulphate is formed.

Question How the colour changes when the gases after thermal decomposition of ferrous sulphate come in contact with an acidified solution of potassium dichromate? Answer: c The color changes from orange to green due to the formation of iron III sulphate.

The representation of chemical reaction by means of symbols of substances in the Ncert Solutions Class 10th Chapter 8 Chem form of formulae is called chemical equation. Balanced Chemical Equation. A balanced chemical equation has equal number of atom of each element Ncert Solutions Class 10th Chapter 8 Chem participating in the reaction on both left and right hand sides of the reaction.

According to Law of Conservation of Mass, total mass of the elements present in the products of a chemical reaction has to be equal to the total mass of the element Ncert Solutions Class 10th Chapter 8 Chem present in the reactants. Rusting When iron reacts with oxygen and moisture it forms a red substance called rust.

Corrosion Metals on coming in contact with oxygen, water, acids or gases presents in air changes its surface. This is called corrosion for e. Prevention Ncert Solutions Class 10th Chapter 8 Chem � painting, galvanization, oiling, greasing.

Rancidity Oil and fats on exposure to air show a change in taste and smell. This property is known as rancidity. Prevention � adding antioxidants, Vacuum packing, refrigeration, flushing food with nitrogen. The transformation of chemical substance into a new Ncert Solutions Class 10th Chapter 8 Chem chemical substance by making and breaking of bonds between different atom is known a chemical reaction.

Combination Reaction When two elements or one compound and one element or two compounds combine to form a new product. Exothermic Reactions Reactions producing energy are called exothermic reactions. Most of the combination reactions are exothermic in nature. Oxidation Gain of oxygen or removal of hydrogen is called oxidation eg. Reduction Ncert Solutions Class 10th Chapter 8 Chem Gain of hydrogen or removal of oxygen is called reduction. Redox Reactions A chemical reaction in which both oxidation and reduction Ncert Solutions Class 10th Chapter 8 Chem takes place simultaneously are called redox reactions.

Decomposition Reaction When a compound-split into two or more simple products for example Decomposition reaction Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem require energy either in the form of heat, light or electricity for decomposing the reactions. Endothermic Reactions Reactions which require energy to occur Solutions Chem Chapter 10th 8 Ncert Class are known as endothermic reactions. Here O. Here, O. Thus, it is a redox reaction. Therefore, K is oxidised while F 2 Ncert Solutions Class 10th Chapter 8 Chem Chem Solutions 8 Chapter 10th Class Ncert Ncert Solutions Class 10th Chapter 8 Chem is reduced. By chemical bonding, C 2 is attached to three H-atoms less electronegative than carbon and one CH 2 OH group Ncert Solutions Class 10th Chapter 8 Chem more electronegative than carbon , therefore, O.

Question 4. Answer: Writing the O. Therefore, F 2 is both reduced as well as oxidised. Thus, it is a redox reaction and more specifically, it is a disproportionation reaction. Question 5. Suggest structure of these compounds. Count for the fallacy. Answer: O. By conventional method, the O. This fallacy is overcome if we calculate the O. Question 6.

Question 7. Question 8. While sulphur dioxide and hydrogen peroxide can act as an oxidising as well as reducing agents in their reactions, ozone and nitric acid act only as oxidants. Answer: i In S0 2 , O. In principle, S can have a minimum O. Therefore, S in S0 2 can either decrease or increase its O. In principle, O can have a minimum O.

Therefore, O in H 2 O 2 can either decrease its O. Therefore, H 2 O 2 acts both as an oxidising as well as Ncert Solutions Class 10th Chapter 8 Chem a reducing agent. It can only decrease its O. Therefore, O 3 acts only as an oxidant. Therefore, it can only decrease its O. Question 9. Answer: a Therefore, it is more appropriate to write the equation for photosynthesis as iii because it emphasises that 12H 2 O are used per molecule of carbohydrate formed and 6H 2 O are produced during the process.

The path of reactions a and b can be determined by using H 2 0 2 18 or D 2 0 in reaction a or Ncert Solutions Class 10th Chapter 8 Chem by using H 2 0 2 18 or O Ncert Solutions Of Class 10th Chapter 7 Exercise 7.2 Vis 3 18 in reaction b. Question The compound AgF 2 is unstable. However, Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem if formed, the compound acts as a very strong oxidising agent. Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if oxidising agent is in excess.

Justify this statement giving three illustrations. Answer: i C is a reducing agent while O 2 is an oxidising agent. When excess of Na is used, sodium oxide is formed in which the oxidation Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem state of O is If, however, excess of 02 is used, Na 2 O 2 is formed in which the oxidation state of O is -1 which is higher than How do you account for the following observations? Write a balanced redox equation for Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem the reaction. Answer: a Toluene can be oxidised to benzoic acid in acidic, basic and neutral media according to the following redox equations: In the laboratory, benzoic acid is usually prepared by alkaline KMnO 4 oxidation of toluene.

However, in industry alcoholic KMnO 4 is preferred over acidic or alkaline KMnO 4 because of the following reasons: i The cost of adding an acid or the base Ncert Solutions Class 10th Chapter 8 Chem Ncert 8 Class 10th Chapter Chem Solutions is avoided because in the neutral medium, the base OH- ions are produced in the reaction itself. H 2 S0 4 is added to an inorganic mixture containing chloride, a pungent smelling gas HCl is produced because a stronger acid displaces a weaker acid from its salt.

However, when the mixture contains bromide ion, the initially produced HB r being a strong reducing agent than HCl reduces Ncert Solutions Class 10th Chapter 8 Chem H 2 S0 4 to S0 2 and is itself oxidised to produce red vapour of Br 2. Identify the substance oxidised, Ncert Solutions Class 10th Chapter 8 Chem reduced, oxidising agent and reducing agent for each of the following reactions.

Consider the reactions: Why does the same reductant, thiosulphate react difforerently with iodine and bromine? Answer: The average O. The O. It is because of this reason that thiosulphate reacts differently with Br 2 and I 2. Justify-giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic add is Ncert Solutions Class 10th Chapter 8 Chem the best reductant.

Answer: Halogens have a strong tendency to accept electrons. Therefore, they are strong oxidising agents. Their relative oxidising power is, Ncert Solutions Class 10th Chapter 8 Chem Ncert Solutions Class 10th Chapter 8 Chem however, measured in terms of their electrode potentials. Conversely, halide ions have a tendency to lose electrons and hence can act as reducing agents.

Since the electrode potentials of halide ions decreases in the order: I � Thus, hydroiodic acid is the best reductant. This Ncert 10th 8 Chem Solutions Class Chapter is supported by the following reactions. Thus, HI is a stronger reductant than HB r. Why does the following reaction occur? Balance Ncert Solutions Class 10th Chapter 8 Chem the following redox reactions by ion-electron method. Balance the following equation in basic medium by ion electron method and oxidation number Ncert Solutions Class 10th Chapter 8 Chem method and identify the oxidising agent and the reducing agent.

Thus, cyanogen is simultaneously reduced to cyanide ion and oxidised to cyanate ion.

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